s(t) = 2t³ - 5t² + 3t + 1
where s(t) is the position in meters and t is time in seconds.
Find the velocity and acceleration of the particle at t = 2 seconds.
11 Views
top of page
Ask & Answer Hub
Public·3 members
bottom of page
s(t) = 2t³ - 5t² + 3t + 1
where s(t) is the position in meters and t is time in seconds.
Find the velocity and acceleration of the particle at t = 2 seconds.
Since s(t) is the is the position , s'(t) represents velocity and s''(t) represents acceleration. Velocity s'(t)= 6t^2 - 10t + 3 given: t=2 s'(2)=6(2)^2 - 10(2) +3 s'(2)=7 m/s Acceleration s''(t)=12t - 10 given: t=2 s''(2)=12(2)-10 s''(2)=14 m/s^2